Sketch Region of Integration, Reverse Order, Confirm Equality

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The discussion focuses on sketching the region of integration for the integral ∫∫dydx with limits 0≤x≤1 and 0≤y≤√x, and reversing the order of integration. The user attempted to rearrange the limits to ∫∫dxdy with 0≤x≤y² and 0≤y≤1 but encountered discrepancies in the evaluated results, yielding 2/3 for the first integral and 1/3 for the second, while the expected answer is 1/6. Participants emphasize the importance of correctly identifying the limits for the reversed integral to ensure the same region is integrated over. Clarification is sought on whether the sketch of the region is accurate and how x and y vary in the new limits. The conversation highlights the need for proper visualization and limit adjustments when changing the order of integration.
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Homework Statement



sketch the region of integration and write an equivalent integral with order of integration reversed. Then evaluate both integrals to confirm their equality

Homework Equations



\int\intdydx for 0<=x<=1 and 0<=y<=\sqrt{x}

The Attempt at a Solution



i rearanged the limits so the equation becomes
\int\intdxdy for 0<=x<=y2 and 0<=y<=1

but my calculations for the first equation came to 2/3 and the second equation came to 1/3

plus the answer is 1/6 so I am obviously doing something wrong. can someone help? have i even written the second equation right?
 
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Did you first sketch the region of integration? The limits for the second integral(with order of integration reversed) should be taken such that you still integrate over the same region. Do you know how to do this?
 
yeh I am pretty sure i drew it properly??
 

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Since your attachment is pending approval, assuming your diagram is correct, think about the new set of limits you have to use when you change the order of integration. How do x and y vary now?
 
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