Sketch Signal: (t-4)[u(t-2)-u(t-4)]

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SUMMARY

The discussion focuses on sketching the signal defined by the expression (t-4)[u(t-2)-u(t-4)]. The term (t-4) represents a ramp function with a slope of 1 that intersects the x-axis at the point (4,0). The expression u(t-2)-u(t-4) describes a rectangular pulse with an amplitude of 1, extending from t=2 to t=4, which effectively acts as a window for the ramp function. To visualize the signal, one should sketch the unit step functions u(t-2) and u(t-4) and then graphically subtract them to understand the resulting waveform.

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DanielleL5432
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The question says to sketch the signal (t-4)[u(t-2)-u(t-4)].
I know that the inner part is a delay of two and a delay of four, but I don't know what to do with the (t-4)...does it have anything to do with the slope?
 
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DanielleL5432 said:
The question says to sketch the signal (t-4)[u(t-2)-u(t-4)].
I know that the inner part is a delay of two and a delay of four, but I don't know what to do with the (t-4)...does it have anything to do with the slope?

t-4 is a ramp with slope 1 passing by the point (4,0).
u(t-2)-u(t-4) is a pulse of amplitude 1 extending from t=2 to t=4. It acts as a window over the function t-4.
 
Sketch U(t-2). Then sketch U(t-4). Now subtract the two graphically. Does that help?
 
hello! could someone please explain to me how u(t)-2u(t-2)+u(t-5) is sketched?
 
eleni_p said:
hello! could someone please explain to me how u(t)-2u(t-2)+u(t-5) is sketched?
+1 anyone?
 
You should sum a step of amplitude 1, starting at t = 0, with a step of amplitude -2 starting at t = 2 and a step of amplitude 1 starting at t = 5.
 

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