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y=x(lnx)^3

The ln scares me a bit... I have found the derivative of the function as 3(lnx)^2, and when making that equal to zero I got an anwer of around 0.7 if i remember correctly. This I guess is my critical number? Then the second derivative is 6/x(lnx). I really am not sure if I am doing this right, especially with the ln in there. Am I on the right track? What can I now do?