SL Atmospheric Pressure Calculation

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Homework Help Overview

The discussion revolves around calculating the pressure at a depth of 11 km below sea level, specifically in the context of atmospheric pressure and water pressure. The subject area includes fluid mechanics and pressure calculations.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the equation for pressure and the necessary parameters, including gravitational acceleration and density. There is confusion regarding the appropriate units for height and the conversion needed. Some participants suggest considering the weight of a column of water and question the density value used.

Discussion Status

The discussion is ongoing, with participants providing insights and clarifications about the problem setup. Some guidance has been offered regarding the interpretation of the question and the use of specific density values, but no consensus has been reached on the correct approach or calculations.

Contextual Notes

There is mention of potential confusion regarding the density of water and whether it should be treated as constant. Participants are also navigating the distinction between atmospheric pressure and water pressure at depth.

zenmasterwombles
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Im glad this website is here for help, cause physics is nuts, but i enjoy it.

question is at 11km below sea level what is the pressure in atmosphere.

now I've got the equation p=(h)(g)(d)

ive got g=9.8 m/s d=1030kg/m3 (given to us) but the height is what is throwing me off, in my notes i have that it needs to be converted, but to what columns? i have that written down but can't find anywhere if columns is what it needs to be in or what, if someone can tell me what to convert the columns into that would be very helpful, thank you
 
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zenmasterwombles said:
Im glad this website is here for help, cause physics is nuts, but i enjoy it.

question is at 11km below sea level what is the pressure in atmosphere.

now I've got the equation p=(h)(g)(d)

ive got g=9.8 m/s d=1030kg/m3 (given to us) but the height is what is throwing me off, in my notes i have that it needs to be converted, but to what columns? i have that written down but can't find anywhere if columns is what it needs to be in or what, if someone can tell me what to convert the columns into that would be very helpful, thank you
Think of it as the weight of the air on a 1 m^2 area. The pressure at 11 km below sea level is the pressure at sea level plus the weight of this 1 m^2 x 11km column of air.

AM

P.S. Better check your figure for density of air. You are about 3 decimal places out.
 
Last edited:
Find the pressure at the depth and then divide it by atmospheric pressure. A pressure of 2 atm. means the pressure is twice as that of atmospheric pressure.

(Check whether the density of water is to be taken constant!)

MP
 
I misunderstood the question. I thought it was asking what the atmospheric pressure would be at a depth of 11 km. It is asking what the water pressure would be at a depth of 11km in the ocean.

Use the same approach I suggested, but use your 1030 kg/m^3 for the density of sea water. What is the weight of an 11km column of water having an area of 1 m^3? That the the additional pressure.

AM
 

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