Small Rotation about q: How \epsilon \vec{n} \times \vec{q} Works

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Homework Statement


My book says that [tex]\epsilon \vec{n} \times \vec{q}[/tex] represents a small rotation about q.
n is an normal vectors
Obviously the cross product is orthogonal to both n and q, but I did not know it corresponded to an angle?
BY the way, how do you make a cross product in tex?

Homework Equations


The Attempt at a Solution

 
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cross product in tex? \times will be fine

the epsilon correspond to the small amplitude of your infinitestimal rotation I think
 
It doesn't represent an angle. It represents an infinitesimal displacement. A small displacement from a vector q rotated around an axis along n should be perpendicular to both. Hence nxq.