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## Homework Statement

When resistors 1 and 2 are connected in series, the equivalent resistance is 14.7 Ω. When they are connected in parallel, the equivalent resistance is 2.56 Ω. What are (a) the smaller resistance and (b) the larger resistance of these two resistors?

## Homework Equations

1/Req=1/R1+1/R2 parallel

R1+R2+Req series

## The Attempt at a Solution

My t.a. said that there would be a substitution and then end up with a quadratic equation. So far i have: R1+R2=14.7ohm

1/R1+1/R2=1/2.56ohm

R1(R2)=2.56(R1+R2) => R1(R2)=37.632ohm

2.56R1+2.56R2-37.632=0 <= my incorrect quadratic which i don't know how to correct.

How can i develop a quadratic from my info? Thanks!