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Smoothing of fullwave rectifying circuits

  1. May 3, 2013 #1
    1. The problem statement, all variables and given/known data
    http://s13.postimg.org/l780tdg1z/screenshot_33.png
    it's b ii)

    2. Relevant equations
    none


    3. The attempt at a solution
    well, I just drew a capacitor in series with the load, but when I looked for the answer it was written that it has to be in parallel, I just wanted to know why?how would it make any difference
    thanks in advance :)
     
  2. jcsd
  3. May 3, 2013 #2
    Imagine that the rectifier produces perfect DC output, and you had the capacitor in series with the resistor. What would be the steady state power dissipated by the resistor?
     
  4. May 3, 2013 #3
    if you mean by perfect DC output that it doesn't need any smoothing(like the voltage is constant)
    I think that there will be no power dissipated by the resistor,because the capacitor is fully charged.is that correct?
     
  5. May 3, 2013 #4
    Yes, that it what I meant. The capacitor in series essentially blocks the DC current.
     
  6. May 3, 2013 #5
    ahh, ok. thank you very much :)
     
    Last edited: May 3, 2013
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