Smoothing of fullwave rectifying circuits

[bubakazouba]

Homework Statement

http://s13.postimg.org/l780tdg1z/screenshot_33.png
it's b ii)

Homework Equations

none

The Attempt at a Solution

well, I just drew a capacitor in series with the load, but when I looked for the answer it was written that it has to be in parallel, I just wanted to know why?how would it make any difference
thanks in advance :)

 

[MisterX]

Imagine that the rectifier produces perfect DC output, and you had the capacitor in series with the resistor. What would be the steady state power dissipated by the resistor?

 

[bubakazouba]

if you mean by perfect DC output that it doesn't need any smoothing(like the voltage is constant)
I think that there will be no power dissipated by the resistor,because the capacitor is fully charged.is that correct?

 

[MisterX]

Yes, that it what I meant. The capacitor in series essentially blocks the DC current.

 

[bubakazouba]

Yes, that it what I meant. The capacitor in series essentially blocks the DC current.

ahh, ok. thank you very much :)