Snells Law and a triangle prism

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SUMMARY

The discussion revolves around Snell's Law applied to a right-angle prism with angles measuring 32 degrees and 58 degrees. A light ray entering the prism at a right angle splits into two rays diverging at 8.5 degrees, with the first ray being 12 degrees lower than the initial angle of incidence. The participants aim to calculate the index of refraction for each wavelength using the formula nsin(theta) = nsin(theta), with air's refractive index set at 1. Calculations involve sin(70)/sin(58) and sin(78.5)/sin(58) to determine the indices.

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  • Understanding of Snell's Law and its application in optics
  • Basic knowledge of light refraction principles
  • Familiarity with angle measurements in triangles
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Punkyc7
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A light ray in air strikes the flat side of a right angle prism at a right angle. The prism has 32 58 as the other angles with 32 degrees being in the bottom and the right angle being to the right of it. The light ray consist of two different wavelenghts. When it emerges at the face AB. It was been split into two different rays that diverge from each other at 8.5 degrees. The first ray is 12 degrees lower then when the initial ray strikes the prism

Find the index of refraction of the prism for each of the two wavelenghts?

nsintheta=nsintheta


since air is 1 is it just

sin70/sin 58

and

sin78.5/sin58
 
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A diagram would be nice.
 

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