hey folks, so heres the deal, I have a isolation transformer that I use for my self wound irons.one of them is working good , heats up nicely and i solder with it all the time, the other one is an old iron , its bigger i want to use it were bigger parts need to be soldered. heres the problem, my transformer outputs about 42 to45 volts AC on secondary, I wound the iron but I guess i made the coil a bit too long , it heats up but not as hot as it would need to be , now i basically have three options, option nr.1 take the iron open and adjust the coil, now i would not like this idea because i already tightened the iron and packed it really good and the mica thermoelectric insulation is very very fragile. option nr.2, take the secondary winding and put some extra turns around the core to step up voltage. option nr.3 and this is the question , if i would attached a bridge rectifier and some smoothing capacitors it would make the voltage from AC to DC and around 63 volts DC, since 45vAC x1.414= 63.63, now would rectifying the AC into DC heat up the iron more than the 45 volt AC? I think it should because the power that goes into a given resistance is determined by the resistance and the voltage across that resistance which determines the current, so a 63v DC supply should push more current than a 45v AC supply correct?