What is the meaning of ##d\Omega## in solid angle integration?

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PreposterousUniverse
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Anyone have any idea how to perform the following two integrals?

##\int d\Omega n_{i}n_{j}## and ##\int d\Omega n_{i}n_{j}n_{k}n_{l}##

where the n is a unit vector.
 
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Not if you don't provide some more context. The way it looks now (to me) it's nonsense (##n_in_j = \delta_{ij}## ? )
 
BvU said:
Not if you don't provide some more context. The way it looks now (to me) it's nonsense (##n_in_j = \delta_{ij}## ? )
Actually, I think it should be proportional to some symmetrized product of kronecker deltas. But how can one show that?
 
PreposterousUniverse said:
But how can one show that?
First you have to show what you mean. Isn't a unit vector a constant of the integration ?

Describe ##\;d\Omega##