Solid rocket velocity and distance

4 replies · 2K views · last reply
MCarsten
Messages
3
Reaction score
0
Hi there. I'm new to the forum. I apologize if I'm posting at the wrong session. Anyway, here goes the problem: (sorry for any grammar typos).

A solid fuel rocket, home constructed, has initial mass 10 kg; this, fuel is 8 kg. The rocket is launched vertically, from rest; burning the fuel at a constant rate equal to 0.225 kg/s, ejecting the exhaustion gases at a speed of 1980 m/s in relation to the rocket. Assume that the outlet pressure is the atmospheric and that the air resistance can be neglected. Calculate the velocity of the rocket 20 seconds after the launch and the distance traveled in the same interval.

I tried to find the velocity through the integral equation of the conservation of mass, but I do not have the areas. I could assume that they simplify, although I am not sure how to deal with the specific mass or volume, since they vary. I imagine that the values will come by through some ODE.

Thanks, in advance.
 
MCarsten said:
Hi there. I'm new to the forum. I apologize if I'm posting at the wrong session. Anyway, here goes the problem: (sorry for any grammar typos).

A solid fuel rocket, home constructed, has initial mass 10 kg; this, fuel is 8 kg. The rocket is launched vertically, from rest; burning the fuel at a constant rate equal to 0.225 kg/s, ejecting the exhaustion gases at a speed of 1980 m/s in relation to the rocket. Assume that the outlet pressure is the atmospheric and that the air resistance can be neglected. Calculate the velocity of the rocket 20 seconds after the launch and the distance traveled in the same interval.

I tried to find the velocity through the integral equation of the conservation of mass, but I do not have the areas. I could assume that they simplify, although I am not sure how to deal with the specific mass or volume, since they vary. I imagine that the values will come by through some ODE.

Thanks, in advance.

There are numerous papers and articles about such "variable mass" dynamical systems; in particular, Google 'rocket equation'.
 
Ray Vickson said:
There are numerous papers and articles about such "variable mass" dynamical systems; in particular, Google 'rocket equation'.

Yes. I googled for that. Although they all deal with force and that's not the case of the problem. Or at least, that's what I guess. As I said above, I think it is only a problem of conservation of mass, not momentum. Nevertheless, I will give a second look.
 
MCarsten said:
Yes. I googled for that. Although they all deal with force and that's not the case of the problem. Or at least, that's what I guess. As I said above, I think it is only a problem of conservation of mass, not momentum. Nevertheless, I will give a second look.
If the rocket is burning fuel and ejecting the exhaust out the back, how can this be a conservation of mass?
 
SteamKing said:
If the rocket is burning fuel and ejecting the exhaust out the back, how can this be a conservation of mass?

You are right. My mistake. I thought the problem could be simplified only to a conservation of mass.

I searched for some equations on the internet and I solved like this:

Equation R = dm/dt, where R is a rate and dm/dt is the time derivative of mass m, written as a fraction.


Integral of R dt from t0 to t, written as m(t) = m0 - Rt, with the mass-loss relation dm/dt = -R shown in the derivation.


where "m0" is (rocket material + rocket fuel) and "R" is the constant rate of exhaustion. So, m0 = 10 kg and R = 0.225 kg/s. This yields m(t) = 5.5 kg.

Applying Tsiolkovsky rocket equation:

Equation: m dv/dt = -v_rel dm/dt, relating rocket mass, velocity, relative exhaust speed and mass flow rate.


Equation v = -v_rel ln(m0/m) written as plain text in LaTeX-rendered form, the Tsiolkovsky rocket equation with v_rel and m0 over m inside a natural logarithm.


So:

Handwritten calculation: v = -1980 m/s · ln(10 kg / 5.5 kg), followed by v = -1183.71 with a question mark.
(m/s)

But this yields a negative velocity (not forgetting to mention that the rocket is displacing itself at a rate of 1.18 km/s). What have I done wrong?