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## Homework Statement

Solve for the interval 0 < x < pi/2

[tex]\sqrt{5}Cos(2x+0.464)[/tex]

## Homework Equations

## The Attempt at a Solution

Am i right in saying as cos oscillate between -1 and 1:

The maximum is sqrt(5) and occurs when (2x-0.464) = 1

Now i got 0.464/2 and (2pi - 0.463)/2

and the back of the book says 0.32 and 2.36

How do you solve equations like above :S

Thanks

yes my calculator is in radians.