Solution to Classical Mechanics Problem: Removing Constant Terms

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SUMMARY

The discussion centers on the removal of constant terms in the potential energy equation for a classical mechanics problem involving small oscillations. The potential energy is expressed as V = mg(l2/2 + l1/2 θ1² + l2/4 θ2²). Participants confirm that the constant term mg(l2/2) can be disregarded when constructing the matrix Vjk, as it does not affect the dynamics of the system. The resulting matrix is Vjk = mg * [[l1, 0], [0, l2/2]], which accurately represents the system's behavior without the constant term.

PREREQUISITES
  • Theory of small oscillations
  • Matrix representation in classical mechanics
  • Understanding of potential energy in physics
  • Basic calculus for approximations (e.g., Taylor series)
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  • Study the derivation of potential energy in classical mechanics
  • Learn about the implications of constant terms in Lagrangian mechanics
  • Explore matrix methods for solving systems of differential equations
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Students and professionals in physics, particularly those focusing on classical mechanics and small oscillations, as well as educators seeking to clarify concepts related to potential energy and matrix representations.

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Ayo everybody, I'm doing a problem about theory of small oscilatons (see pic) and I got the following for potential energy:

V= mg(\frac{l_{2}}{2} +\frac{l_{1}}{2} \theta^{2}_{1} + \frac{l_{2}}{4} \theta^{2}_{2}) (after the aproximation cos \theta~ 1 - \frac{\theta^{2}}{2}

Knowing that V = \frac{1}{2} V_{jk} \theta_{jk} I need to write the matrix V_{jk}

Since the term mg\frac{l_{2}}{2} is constant, can I remove it from the potential ?

And write the matrix like this:

V_{jk} =mg \begin{pmatrix}<br /> l_{1} &amp; 0 \\<br /> 0 &amp; \frac{l_{2}}{2} \\<br /> \end{pmatrix}<br />

If not, how can I remove the constant term?
 

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Constant terms don't matter, you can ignore them. They just reflect the arbitrary choice of "zero height".
 
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