Solution to Continuous Function: Find x in [0,1] with f(x)=x

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SUMMARY

The discussion centers on demonstrating the existence of a value x in the interval [0,1] such that f(x) = x for a continuous function f defined by f(0) = 1 and f(1) = 0. The key insight is the application of the Intermediate Value Theorem, which confirms that since g(x) = f(x) - x transitions from a positive value (g(0) = 1) to a negative value (g(1) = -1), there must be at least one point in [0,1] where g(x) = 0, thus proving f(x) = x. This conclusion is essential for understanding fixed-point theorems in calculus.

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  • Understanding of continuous functions
  • Familiarity with the Intermediate Value Theorem
  • Basic knowledge of function notation and evaluation
  • Concept of fixed points in mathematical analysis
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  • Study the Intermediate Value Theorem in detail
  • Explore fixed-point theorems in calculus
  • Learn about continuous functions and their properties
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Students of calculus, mathematicians interested in analysis, and educators teaching fixed-point theorems will benefit from this discussion.

jmich79
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Suppose that f is ais continuos function defined on [0,1] with f(0)=1 and f(1)=0. show that there is a value of x that in [0,1] such that f(x)=x.
I just do not understand this concept. Cna someone worjk this problem out for me and explain what's going on? Thank You.
 
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You take a look at f(x)-x=g(x)

g(0)=1-0=1
g(1)=0-1=-1

So on [0,1] g is continuous and goes from 1 to -1. Hence, the intermediate value theorem gives you your answer. This is like, the third thread you've made on this, and if you can't get the answer from this post, you should probably go look up the intermediate value theorem and see what it actually says
 

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