Solve 2-Particle Elastic Collision: Mass m & Final Velocity -v/5

AI Thread Summary
In an elastic collision involving two particles, one with mass m is initially at rest, while the other has an initial velocity v and a final velocity of -v/5. The mass of the second particle can be determined using conservation of momentum and kinetic energy equations. By substituting known values into the equations, the mass of the second particle is found to be 2m/3. The discussion highlights the challenge of solving for two unknowns without specific numerical values. Ultimately, the calculations confirm the relationship between the masses post-collision.
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Hey, just doing some homework, and can't figure this one out

Homework Statement


Two particles go through an elastic collision. One particle has mass, m, and is initially at rest, while the other particle has initial velocity, v, and final velocity, -v/5. What is the mass of the second particle relating to m.

Answer: 2m/3

Homework Equations


The Attempt at a Solution


What I'm confused about is because you have two unknowns, the final velocity of the resting particle, and the mass of the second particle..

i tried using

m1v1 + m2v2 = m1v1' + m2v2'
and .5m1(v1)2 + .5m2(v2)2 = .5m1(v1)2' + .5m2(v2)2'

that seems waay too confusing for a question with no values..
 
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You can imagine that m and v are numerical values. Just plug in m1=m, v1=0 (initially in rest), v2=v, v2' = -v/5 into your equation and solve for m2/m.

ehild
 
ehild said:
You can imagine that m and v are numerical values. Just plug in m1=m, v1=0 (initially in rest), v2=v, v2' = -v/5 into your equation and solve for m2/m.

ehild

yes :smile: i figured it out last night, and when I have time I'll post the answer up here, it's really long haha

thanks ehild!
 
Is it long really? :smile:

m2 v=m v'-m2v/5
m2 v2=m v'2+m2v'2/25

mv'=6/5 m2 v *
mv'2=24/25 m2v2 **

Divide equation ** by eq. *

v' = 4/5 v

Substitute for v' in eq.*.

ehild
 
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