Solve Columns Law Problem: Magnitude of 3rd Charge

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Homework Help Overview

The problem involves three charged objects positioned along the x-axis, with specific charges and locations. The objective is to determine the magnitude of the third charge based on the net force acting on it, which is provided.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss using Coulomb's law to calculate the forces exerted on the third charge by the other two charges. There is an attempt to set up an equation based on the net force and the individual forces from the other charges.

Discussion Status

Some participants have provided guidance on how to approach the problem, suggesting the use of Coulomb's law and the importance of correctly converting charge units. There is acknowledgment of potential errors in calculations and the need for verification of results.

Contextual Notes

Participants note the necessity of using consistent units for charge in the calculations, indicating that the original poster may have used incorrect values in their equations. There is also a mention of uncertainty regarding the correctness of the original calculations.

iamtrojan3
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Homework Statement



Take three charged objects and place them on the x-axis. The first charge is + 11 microC, and is placed at +0.85 m. The second charge is -4.6 microC, and is placed at -0.22 m. The third charge is placed at the origin. If the net force on the third charge has a magnitude of 6.0(10-4) N, what is the magnitude of the charge?


Homework Equations



F=k (q1q2)/r^2

The Attempt at a Solution




i can find each charge magnitude in respect to the 3rd charge with the equation, but don't no where to go from there.
Thanks
 
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Show exactly what you did. Hint: Call the unknown charge Q. Use Coulomb's law to solve for the force exerted on that charge by each of the other two charges.
 
ok i got my answer but I am not sure if its right.
basically i added 2 of coulombs equations 2gether.
6E-4= K(4.6xq2)/(0.22^2)+ K(11xq2)/(0.85^2)
after some algebra
6E-4=8.5E11q2+1.37E11q2
Factor out q2
q2= 6E-4/9.87E11
i got q2 to be around 6E-16 Micro C which = 6E-10 C
the answer is suppose to be "6.1E-10C". It might rounding error or i might be wayyyy off.
Can someone please check this?
Thanks
 
iamtrojan3 said:
ok i got my answer but I am not sure if its right.
basically i added 2 of coulombs equations 2gether.
6E-4= K(4.6xq2)/(0.22^2)+ K(11xq2)/(0.85^2)
The charges are in microC, so they should be 4.6E-6 & 11E-6 C in this equation. That should explain why your answer is so far off.
 
yes, but is my train of thought even close to what your suppose to do?
 
Your method is perfectly correct. Fix those charge values and you should get the right answer.
 

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