Solve Density Problem: Mercury in Lake | Mass = 6 x 105 kg

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The discussion revolves around calculating the total mass of mercury in a polluted lake, given a concentration of 0.4 μg Hg/mL, a surface area of 100 mi², and an average depth of 20 ft. Participants clarify that the provided concentration is a measure of pollution rather than density, which complicates the calculation. The initial calculations yield a mass of 6 x 10^5 kg, but the textbook suggests the answer is 7 x 10^5 kg. There is a consensus that the approach taken is correct despite the discrepancy in the final answer. The conversation highlights the importance of distinguishing between concentration and density in such calculations.
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Homework Statement



Mercury poisoning is a debilitating disease that is often fatal.
In the human body, mercury reacts with essential enzymes
leading to irreversible inactivity of these enzymes. If the
amount of mercury in a polluted lake is 0.4 μg Hg/mL, what
is the total mass in kilograms of mercury in the lake? (The lake
has a surface area of 100 mi2 and an average depth of 20 ft.)

Homework Equations



mass = density * volume

The Attempt at a Solution



I tried converting the density to Kg and the volume to cm3 = mL

Mass = density * volume

= ( (0.4 μg)(1 g/ 106 μg) (10-3 kg / 1 g) ) * ( (100 mi2)(52802 ft2 / 1 mi2)(30.482 cm2 / 1 ft2) (20 ft)(30.48 cm / 1 ft) )

My answer is 6 x 105 kg however the textbook says it's 7 x 105 kg.
 
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0.4 μg Hg/mL is not a density, it is a concentration. Accidentally, it requires the same approach. I got 6x105 as well.
 
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