- #1
Solve FBD Problem: M.asinθ=N, N.sinθ=Ma
- Thread starter hav0c
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SUMMARY
The discussion centers on solving the force balance dynamics (FBD) problem represented by the equations M.asinθ=N and N.sinθ=Ma. The user seeks clarification on the correctness of these equations and explores the horizontal components of forces and accelerations. The consensus is that the proposed equation M.asinθ+M.gcosθ=N is incorrect due to the absence of gravitational force in the provided diagram. The user ultimately concludes that the derived equations are ineffective for solving the problem.
PREREQUISITES- Understanding of Newton's second law (F=ma)
- Knowledge of vector components in physics
- Familiarity with force balance diagrams (FBD)
- Basic trigonometry related to angles in physics
- Study the application of Newton's second law in vector form
- Learn about deriving equations from force balance diagrams (FBD)
- Explore the concept of normal force in physics problems
- Investigate the role of gravitational force in dynamic systems
Students in physics, particularly those studying mechanics, as well as educators and anyone involved in solving force balance dynamics problems.
- #2
voko
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Forces and accelerations are vectors. Once you have Newton's second law in the vector form, you obtain equations for the components of forces and accelerations. In this case, you only care about the horizontal components. What are they?
- #3
hav0c
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horizontal components
of acc. are-- a and (nsinθ)/m
and force are-- ma and nsinθ
but my main question is that is my equation 3 correct?
of acc. are-- a and (nsinθ)/m
and force are-- ma and nsinθ
but my main question is that is my equation 3 correct?
- #4
voko
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hav0c said:
It is not that "a and (nsinθ)/m" are "acceleration components". a = (nsinθ)/m is the horizontal acceleration component.
I do not see any "g" in the picture so based solely on the picture, that equation is definitely wrong.
- #5
hav0c
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I have taken g to be the acceleration downwards due to gravityvoko said:
- #6
voko
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Perhaps you need to describe your problem in full detail. What you have now makes little sense.
- #7
- #8
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As are the diagrams. Please state the question exactly as it was given to you.hav0c said:
- #9
hav0c
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I wasnt having any actual problem in solving questions it was just that i wanted to check whether or not i could derive relations by using different x-y directions, but the new general equations turned out to be useless.