Solve for Distance Sliding in Socks with Friction of .250

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Homework Help Overview

The problem involves calculating the distance a person slides while wearing socks on a surface with a known coefficient of friction. The initial speed of the person is provided, and the context centers around the application of concepts from physics related to friction and energy.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between kinetic energy and work done by friction, exploring equations related to energy conservation and frictional force. Questions arise about the correct application of these concepts and how to isolate the variable for distance.

Discussion Status

Some participants have offered guidance on isolating the variable for distance and have confirmed the correctness of the approach taken. There is an ongoing exploration of the relationship between the variables involved, with no explicit consensus reached yet.

Contextual Notes

Participants mention confusion regarding the role of mass in the equations, noting that it cancels out in the context of the problem. The discussion reflects a focus on understanding the underlying principles rather than simply arriving at a solution.

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[SOLVED] Sliding in Socks

Homework Statement



Suppose that the coefficient of friction between your feet and the floor, while wearing socks, is 0.250. Knowing this, you decide to get a running start and then slide across the floor.

If your speed is 3.00 m/s when you start to slide, what distance d will you slide before stopping?

The Attempt at a Solution



We are given that coefficient of friction is .250

f = .250(n)

I really don't know to go from here.

We are given speed so, let me permit my brain to flow with the numbers :D

K= .5mv^2 may apply

.250mg = .5m(.250)^2
.250(9.8)m = .5m(.250)^2
2.45m = .003125m...and it ends there..so I just went the wrong way.

Solution is 1.84m, but I want to learn how to do this problem.
 
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ok

I got that

k1 = .5mvo^2
k2 = .5mv^2

f = umg

W = F *s

we know that f is a F so I could use that

so

W = -fd = -umgd
Wtotal = k2-k1

so I would think it would be safe to say taht

k2-k1 = -umgd

.5(mv^2) - .5(mvo^2) = -umgd

is this is all correct thusfar, how do I continue?
 
Last edited:
Looks good. Just solve for d. (Isolate d on one side.)
 
yep got it, at first, I was confused on what to do with the m, and realized that they are common factor and cancel out.
 

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