Solve for Intensity: Easy Formula Manipulation for Finding Intensity

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SUMMARY

The discussion focuses on solving the equation for intensity, specifically B = 10log(I/Io). The correct manipulation leads to the formula I = Io * 10^(B/10). Participants clarify the steps involved in isolating I, emphasizing the importance of accurate values for Io and B to avoid errors in calculations. Doc Al's equation is confirmed as correct, providing a clear path for users to derive intensity from the given parameters.

PREREQUISITES
  • Understanding of logarithmic functions
  • Familiarity with algebraic manipulation
  • Knowledge of the intensity reference value (Io)
  • Basic grasp of scientific notation
NEXT STEPS
  • Study logarithmic properties and their applications in physics
  • Learn about intensity calculations in acoustics and optics
  • Explore advanced algebraic techniques for solving equations
  • Investigate common errors in logarithmic equations and how to avoid them
USEFUL FOR

Students in physics or engineering, educators teaching logarithmic functions, and anyone involved in calculations related to intensity in various scientific fields.

Sucks@Physics
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I'm trying to find the intensity of something. I know the equation is

B = 10log(I/Io)

But how to I solve for I? What would the equation be? For some reason I can't make it work.
 
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logarithms

Does this help?
If a = log(b)

then b = 10^a
 
No, i still can't ge thte correct equation, i come up with something like (10x10^B)/Io
 
Rewrite the equation as
I/I0 = 10^(B/10)
 
Last edited by a moderator:
Sucks@Physics said:
No, i still can't ge thte correct equation, i come up with something like (10x10^B)/Io

Not quite:
B = 10log(I/Io)
B/10 = log(I/Io)
10^(B/10) = I/Io
I = Io*10^(B/10)
 
Thanks, that is kinda tricky, but now i understand it
 
From the provided information, Doc Al's equation is correct. You may be using wrong values for your Io and B, or your intensity equation could be incorrect.
 

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