Solve for Time in Air: Baseball Hit Problem | 30 m/s at 30 deg | Window at 12m

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SUMMARY

The discussion focuses on calculating the time a baseball is in the air after being hit at a velocity of 30 m/s at an angle of 30 degrees, with the initial height set at 1 meter and the target window at 12 meters. The equation used is Y = Yo + Vo*t - 1/2*g*t^2, where Vo represents the initial velocity, Yo is the initial height, g is the acceleration due to gravity, and t is time. The initial assumption of Vo as 0 m/s was incorrect, leading to a miscalculation of the time in the air, which should be accurately derived from the correct interpretation of the variables.

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Homework Statement


After you hit a baseball, it flies into a window across the street. The baseball leaves your bat at a distance 1m above the ground, and the window is 12 m above the ground. The ball leaves your bat with a velocity of 30 m/s at 30 degrees.

How long was the ball in the air? Note: if your solution contains two roots, explain the meaning of each.


Homework Equations



Y = Yo + volt - 1/2gt^2


The Attempt at a Solution



With that formula in #2. Vo = 0 m/s so Y = -1/2gt The magnitude of that gives me 3.06 s, but that does not correspond to the answer in the back of the book
 
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Your attempted solution is not very detailed. Think about the meaning of each variable in the equation. You assumed Vo to be zero, but you know that stands for the initial velocity, right? Initial velocity of the ball is obviously not 0. Also Yo stands for initial height.
 

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