Solve for Vo in Transistor Circuit

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Discussion Overview

The discussion revolves around solving for the output voltage (Vo) in a transistor circuit, focusing on the application of Kirchhoff's Voltage Law (KVL) in analyzing the circuit. Participants are attempting to derive Vo based on given parameters and circuit conditions.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents their calculations for Vo, using KVL for two loops and arrives at Vo = 4.7V, but expresses uncertainty about their result.
  • Another participant points out an error in the first participant's KVL equation, suggesting that the 2V and 0.7V should subtract instead of add, leading to a different equation.
  • The same participant reiterates their confusion after adjusting their calculations based on the feedback, resulting in a new value of 7.87V.
  • A later reply indicates another mistake in the right-hand loop and provides a new calculation for Ib, suggesting Ib = 25μA, Ic = 2.5 mA, and concludes with Vo = 5.0V.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct value of Vo, with multiple competing calculations and interpretations of the circuit analysis presented.

Contextual Notes

Participants express uncertainty about specific values and calculations, indicating potential missing assumptions or errors in their reasoning without resolving these issues.

Tekneek
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Homework Statement


So I am supposed to find Vo in this circuit. Given, Vb-Ve=0.7, ic=100ib, ie=ic+ib

The Attempt at a Solution


In order to solve for Vout i did KVL for the two loops:

Loop 1 (left side, clockwise):

Vb-Ve-ie(416)+2-ib(10*103)=0
0.7-ic(416)-ib(416)+2-ib(10*103)=0
0.7-ib(100)(416)-ib(416)+2-ib(10*103)=0
2.7-52016ib=0
ib=5.19*10-5A

ic=5.19mA
ie=ic+ib=5.2mA
Ve=ie(416)=2.18V (this one i am not sure)

Loop 2 (Right side, anti-clockwise)

10-ic(2*103)-Vo-Ve-ie(416)=0
Subbing in everything i get
Vo=4.7V

But the answer is supposed to be 5 Volts, i am not sure where i made a mistake.

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The 2V and the 0.7V in the left hand loop are in opposite directions, so they should subtract, not add, so you should get 1.3-52016*Ib=0.
 
Last edited:
phyzguy said:
The 2V and the 0.7V in the left hand loop are in opposite directions, so they should subtract, not add, so you should get 1.3-52016*Ib=0.

I still don't get the right answer, this time around i get 7.87
 
You've made another mistake in the right hand loop, but you don't really need that. With what I gave you, you should get Ib = 25μA. Ic = 100* Ib = 2.5 mA. Vout = 10.0 - 2.5mA * 2.0 kΩ = 5.0V
 

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