goosey00
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Solve for x:e^-0.38x=.3
I got .4387 Is that correct
I got .4387 Is that correct
The discussion focuses on solving the exponential equation e-0.38x = 0.3. The initial answer of 0.4387 is confirmed incorrect after evaluating e-0.38 * 0.4387, which yields approximately 0.8467. The correct method involves taking the natural logarithm (ln) of both sides, leading to the solution x = ln(0.3) / -0.38, which calculates to approximately 3.1683.
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goosey00 said:Solve for x:e^-0.38x=.3
I got .4387 Is that correct
goosey00 said:I just can't remember how to put it in my calculator again. How did you get the .4387 to times by it-[FONT=MathJax_Math-italic-Web]e [FONT=MathJax_Main-Web]−[FONT=MathJax_Main-Web]0.38[FONT=MathJax_Main-Web]∗[FONT=MathJax_Main-Web]0.4387
[2nd] [ln] [(] [-][0.38] [x] [0.4387][)][=]
[(] [-][0.38] [x] [0.4387][)][2nd] [ln][=]
\text{We have: }\:e^{-0.38x} \;=\;0.3Solve for x:\;e^{-0.38x}\:=\:0.3
I got 0.4387 . Is that correct?
Can't you check your answer?