Solve Gauss's Law and Flux: 55.3M Excess Electrons

[dals2002]

[SOLVED] Gauss's Law and Flux

ok so i have the biggest question of all i tried solving the following problem:

55.3 million excess electrons are inside a closed surface. What is the net electric flux through the surface?

now i tried the following equations:

$$\Phi$$= E . A = Qin/$$\epsilon$$

but i have the biggest question when there is excess electron does it mean that the electron field is negative, and if it does then that goes in Qin where then $$\Phi$$ would be equal to Qin/$$\epsilon$$, and epsilon being 8.85*10 (permittivity constant)

well any help in solving this problem is very grateful

 

[terbum]

You can solve for the enclosed charge, since the elementary charge of an electron (-1.60*10^-19 C) and the number of electrons is known. Just use Q/epsilon to solve for flux.

 

[dals2002]

oh wow that was easy, i always see things harder then they are, thanks terbum