stunner5000pt
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Homework Statement
Griffith's problem 1.12
Calculate [itex]d\left<p\right>/dt.[/itex]
Answer [tex]\frac{d\left<p\right>}{dt} = \left<\frac{dV}{dx}\right>[/tex]
2. The attempt at a solution
so we know that
[tex]\left<p\right> = -i\hbar \int \left(\Psi^* \frac{d\Psi}{dx}\right) dx[/tex]
so then
[tex]\frac{d\left<p\right>}{dt} = -i\hbar \int \left( \frac{\partial\Psi^*}{\partial t} \frac{\partial\Psi}{\partial x} + \Psi^* \frac{\partial^2 \Psi}{\partial t \partial x} \right) dx[/tex]
im not quite sure if one can simplify this further ... i mean we can't integrate wrt x because all the terms in the integrand have x dependance... don't they?? Should i intergate by parts to proceed??
I think a couple of extra terms would be required, no?
Thanks for the help!