Solve Index of Refraction Homework Statement

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SUMMARY

The discussion focuses on solving a physics homework problem involving the index of refraction, specifically applying Snell's Law to find the height (H) in a refraction scenario. The index of refraction for air is treated as 1, while water has an index of 1.33. The relationship between angles and distances is established using trigonometric functions, leading to the equation sin(θ1) = (W/√(W² + H²)). The participants conclude that by substituting known values into Snell's Law, it is possible to isolate H as the only unknown variable.

PREREQUISITES
  • Understanding of Snell's Law and its application in optics
  • Basic trigonometry, including sine and tangent functions
  • Familiarity with the concept of index of refraction
  • Ability to manipulate algebraic equations to isolate variables
NEXT STEPS
  • Study the derivation and applications of Snell's Law in various media
  • Explore advanced trigonometric identities and their use in physics problems
  • Learn about the properties of light refraction and critical angles
  • Practice solving similar refraction problems using different indices of refraction
USEFUL FOR

Students in physics courses, educators teaching optics, and anyone interested in understanding light behavior in different media.

ObliviousSage
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Homework Statement



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Index of refraction of air is being treated as 1, index of refraction for water is 1.33.
W is given as 6.1 cm, the problem is to find H.

Homework Equations



By Snell's Law, n1sin\Theta1=n2sin\Theta2.

We can also use at least one of the trigonometric equations, tan\Theta=opposite/adjacent.

The Attempt at a Solution



Since we know n1 and n2, we can reduce the Snell's Law equation to: sin\Theta1=1.33*sin\Theta2.

We can also get that tan\Theta1=6.1/H and tan\Theta2=3.05/H via basic trig, and these can be combined to get tan\Theta1=2*tan\Theta2.

The problem is that I can't see any way to combine any of those equations that will let me isolate a single variable (H, \Theta1, or \Theta2) so that I can find its value and plug it into solve for the other variables.
 
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In the figure on the left, the angle from the side of the glass to the ray, is equal to the angle of refraction in the figure on the right. You called this angle, θ1.

Therefore,  \sin(\theta_1)=\frac{W}{\sqrt{W^2+H^2\,}\,}\ .

From the given conditions, it's clear that  \sin(\theta_2)=\frac{W/2}{\sqrt{(W/2)^2+H^2\,}\,}\ .

Since, you know W, n1, and n2, you should be able to write Snell's Law with only one unknown.
 
Oh wow, I can't believe I forgot about that! Yeah, that should do it, thanks!
 

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