Solve Inequality: x^2-4|-3|<1 | UofT Calculus

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The discussion focuses on solving the inequality ||(x^2)-4|-3|<1, as presented in a UofT Calculus problem set. Participants suggest a systematic approach by dividing the problem into two cases based on the value of x: (1) x^2 ≤ 4 and (2) x^2 > 4. For the first case, the function simplifies to |x^2-1|<1, while for the second case, it simplifies to |x^2-7|<1. This structured method allows for a clearer understanding of the solutions for x.

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Hey everyone. I'm taking Calculus at UofT and I got a question in a problem set that kind of got me thinking, and well, I'm not sure if I'm doing it correctly. This isn't the exact question, but, how would you go about solving this inequality:
||(x^2)-4|-3|< 1
 
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AnthonyJohnAre said:
Hey everyone. I'm taking Calculus at UofT and I got a question in a problem set that kind of got me thinking, and well, I'm not sure if I'm doing it correctly. This isn't the exact question, but, how would you go about solving this inequality:
||(x^2)-4|-3|< 1

The easiest way is to first gain some insight into the problem by plotting a graph of the function f(x) =||x^2 - 4|-3|.

A systematic way is to split up x into cases: (1) x^2 ≤ 4; (2) x^2 > 4. In case (1) we have f(x) = |4-x^2-3| = |1-x^2| = |x^2-1|. So, for x^2 ≤ 4 we also want |x^2-1| < 1. What do these requirements say about x? In case (2) we have f(x) = |x^2 - 4 - 3| = |x^2-7|, so for x^2 > 4 we also need |x^2-7| < 1. What do these tell you about x?
 
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AnthonyJohnAre said:
Hey everyone. I'm taking Calculus at UofT and I got a question in a problem set that kind of got me thinking, and well, I'm not sure if I'm doing it correctly. This isn't the exact question, but, how would you go about solving this inequality:
||(x^2)-4|-3|< 1

Please check your PMs. You should show your attempt at solving the equation as part of your first post asking for help.
 

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