Solve Laplace Transform: L{tcos(t)}

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SUMMARY

The discussion focuses on solving the Laplace Transform of the function L{t cos(t)}. The user seeks clarification on an alternative method proposed by their professor, which involves taking the partial derivative with respect to 's' of the integral representation of the Laplace Transform. This method simplifies the process by allowing the user to utilize the known Laplace Transform of cos(t), specifically L{cos(t)} = s/(s^2 + 1), and apply the property that te^{-st} = -∂/∂s e^{-st} to switch the order of integration and differentiation.

PREREQUISITES
  • Understanding of Laplace Transforms, specifically L{t cos(t)}
  • Familiarity with integration techniques, including integration by parts
  • Knowledge of differentiation under the integral sign
  • Access to Laplace Transform tables for common functions
NEXT STEPS
  • Study the properties of Laplace Transforms, particularly the differentiation property
  • Review integration techniques, focusing on integration by parts and its applications
  • Learn about differentiation under the integral sign and its implications in Laplace Transforms
  • Consult Laplace Transform tables to familiarize with common transforms such as L{cos(t)} and L{sin(t)}
USEFUL FOR

Students studying engineering mathematics, particularly those focusing on differential equations and Laplace Transforms, as well as educators seeking to clarify teaching methods related to these concepts.

Gogeta007
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Homework Statement



L{tcos(t)}

Homework Equations



Using the laplace transform find the equation.


The Attempt at a Solution



I already have a really long answer. . .I was just wondering if someone can explain this:

Another method (appart from using integration by parts multiple times) was mentioned by my professor, he said to take the partial with respect to s of the integral, which will then just leave the partial laplace transform of cos(t) which can be found trough tables

I remember he explained it but now that I think about it it doesn't make sense:

L {t cos(t)} = (int)infinity0 e-stt cos(t)dt
then you can take the partial with respect to s (d/ds) of that integral, and yo uwould end up with

d/ds [L{cost}] = d/ds [s/(s^2+1)]


cans omeone explain?
I remember he mentioned the potential function
 
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You use the fact that

[tex]te^{-st} = -\frac{\partial}{\partial s}e^{-st}[/tex]

and then switch the order of integration and differentiation.
 

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