Solve Limits Problem: Find Limit as x->infinity

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SUMMARY

The limit as x approaches infinity for the expression \(\frac{5x^3-3x^2+8}{2x^3 + 9}\) is definitively \(\frac{5}{2}\). This conclusion is reached by identifying the highest degree terms in both the numerator and denominator, which are \(5x^3\) and \(2x^3\) respectively. By dividing both the numerator and denominator by \(x^3\) and simplifying, all lower degree terms vanish as x approaches infinity, confirming that the limit is \(\frac{5}{2}\).

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Homework Statement



lim as x->infinity [tex]\frac{5x^3-3x^2+8}{ 2x^3 + 9}[/tex]

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The Attempt at a Solution



I was told you can look at this highest exponent for the num and dem to find the limit, but I'm not sure what that means. In this case would it be 5/2 because the Xs cancel out?
 
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Divide top and bottom by x^3. As x->infinity terms like -3/x go to zero. Get rid of them. So yes, you are left with 5/2.
 
Ok thanks. It makes sense now.
 

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