Solve Magnetic Flux from Straight Wire & Rectangular Loop: Wb

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SUMMARY

The discussion focuses on calculating the magnetic flux through a rectangular loop near a long straight wire carrying a current of 36 A. The magnetic field (B) is calculated using the formula B = μ * I / (2πr), where μ is the permeability of free space (4π x 10^-7 T*m/A). The initial attempt yielded a magnetic flux of 2.70e-6 Wb, which was incorrect due to the non-constant nature of the magnetic field across the area of the loop. The correct approach requires integrating the magnetic field over the area of the loop.

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Homework Statement


A long straight wire carries a current 36 A. A rectangular loop with two sides parallel to the straight wire has sides 7.5 cm and 15 cm with its near side a distance 3 cm from the straight wire as shown in the figure. The permeability of free space is 4π e -7 T*m/A. Find the magnetic flux through the rectangular loop. Answer in units of Wb.

http://img112.imageshack.us/img112/9541/mblf4.jpg
Shot at 2007-07-31

Homework Equations



Magnetic flux = BA
B = u * I / (2*pi*r)


The Attempt at a Solution



I found the magnetic field

B = u * I / (2*pi*r) = (4*pi*10^-7 * 36 A) / (2*pi * 0.03 m) = 0.00024 T
Then I found the area of the rectangle which A = 0.075 * 0.15 = 0.01125

I multipled BA to get the magnetic flux. My final answer was 2.70e-6 Wb but this answer is wrong. Could someone please tell me what I'm doing wrong? Thank you.
 
Last edited by a moderator:
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the magnetic field is not constant throughout the area. therefore you have to integrate B*dA, the flux, from r=3 cm to r=3+7.5= 10.5 cm
 

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