Solve Mirror Equation for Unknown Image Distance & Focal Length

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SUMMARY

The discussion focuses on solving a mirror equation involving an ant's image distance and the focal length of a mirror. The object distance (p) is given as 4.90 cm, and the image height (h') is 4.43 cm, while the object height (h) is 1.03 cm. The relevant equations include the mirror equation (1/p + 1/q = 1/f) and the magnification equation (M = -q/p = h'/h). The solution requires using these equations to find the unknown image distance (q) and the focal length (f) of the mirror.

PREREQUISITES
  • Understanding of the mirror equation and its components (p, q, f)
  • Familiarity with the magnification equation and its application
  • Basic knowledge of optics and image formation
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Practice solving problems using the mirror equation with different object distances
  • Explore the relationship between object height and image height using the magnification equation
  • Investigate the effects of different focal lengths on image formation in concave and convex mirrors
  • Learn about real vs. virtual images in the context of mirror equations
USEFUL FOR

Students studying optics, physics enthusiasts, and anyone seeking to understand the principles of image formation in mirrors.

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Homework Statement



An ant is 1.03 cm tall and stands 4.90 cm in front of an unknown mirror. To its surprise the ant sees an its image which is 4.43 cm tall! What is the the distance to the image? What is the focal length of the mirror?

Homework Equations



The mirror equation: 1/p + 1/q = 1/f

p: object distance
q: image distance
f: focal length

Maybe the magnification equation?: M = -q/p = h'/h

q: image distance
p: object distance
h': image height
h: object height

The Attempt at a Solution



I set the problem up this way:

1/4.90 + 1/q = 1/f

I have no idea how to figure it out beyond this point.

Please help! :blushing:
 
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Try to use the magnification equation... it links p and q.
 

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