Solve Period of a Pendulum Equation | Physics Forum

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The discussion focuses on deriving the equation for the period of a pendulum, specifically proving that \(\omega = \sqrt{\frac{g}{L}}\). The user has reached an equation \(\frac{g}{L}\theta = \omega^2 \theta_{max} \sin(\omega t - \alpha)\) and seeks assistance in simplifying it. The approximation is noted to be most accurate when \(\sin x = x\) in radians. The user is also looking for guidance on eliminating the phase angle \(\alpha\) from the equation.

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Hootenanny
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I have already posted in the physics forum but its gone a bit quiet. I've managed to derrive an equation up to this point. I have \frac{g}{L}\theta = \omega^2 \theta_{max} \sin (\omega t - \alpha) and I need to prove that \omega = \sqrt{\frac{g}{L}}. I'm stuped at this one. Thank's in advance for your help.
 
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well, you need to know that it's only an approximation. It is most accurate when sinx=x (in radians of course).
 
That doesn't help me much all that gives then is \frac{g}{L}\theta = \omega^2 \theta_{max}(\omega t - \alpha)
 
Now I have \theta = \theta_{max} \sin(\sqrt{\frac{g}{L}} t - \alpha ) How Can I remove the \alpha ?
 

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