Solve Poiseuille's Equation: 10mL of Water in 37.50 cm h, 20.22 cm L

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SUMMARY

The discussion focuses on solving Poiseuille's equation to determine the time required to collect 10 mL of water under specific conditions. Given parameters include a height (h) of 37.50 cm, length (L) of 20.22 cm, and a diameter (d) of 0.830 mm. The viscosity of water is stated as 0.00100 Pa·s, and the density is 1000 kg/m³. The calculated pressure (P) is 3678.75 N/m², leading to a volumetric flow rate (Q) of 2.12 x 10^-7 m³/s, resulting in a time (t) of approximately 471,900 seconds to collect the specified volume.

PREREQUISITES
  • Understanding of Poiseuille's law and fluid dynamics
  • Knowledge of unit conversions (e.g., mL to L, cm to m)
  • Familiarity with viscosity and its impact on fluid flow
  • Basic algebra for manipulating equations
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  • Learn about the impact of viscosity on fluid dynamics
  • Study unit conversion techniques for fluid measurements
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This discussion is beneficial for students in physics or engineering, particularly those studying fluid mechanics, as well as professionals involved in hydraulic systems and fluid transport calculations.

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Homework Statement



Assume Poiseuille's law applies. If h = 37.50 cm, L = 20.22 cm, d = 0.830 mm, how many seconds will it take to collect 10 mL of water? Assume that the viscosity of water is 0.00100 Pa s, the density of water is 1000 kg/m3 and the acceleration due to gravity in the lab is 9.81 m/s2. Express your answer to 2 significant figures.



Homework Equations



Q= V/t

Q=pi x r^4 x P/8 x n x L (n = viscosity)





The Attempt at a Solution



Ok, so first I found out the pressure
P= density x height x gravity
= (1000 kg/ m^3)(0.375m)(9.81) = 3678.75 N/m^2

Then I calculated for Q using the second equation = 2.12 x 10^-7

Then I used t=V/Q = 0.10L / 2.12x10^-7
= 4.719 x 10^5

This does not seem remotely correct...eeks

Ty in advance
 
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Hint: Check yer units (1 L = ? m^3; 10 mL = ? L)
 

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