MHB Solve Proving 2 Triangles Cong. w/ Diam & Eq. Triangle (2-Col Proof)

AI Thread Summary
To solve the problem of proving two triangles congruent with a diameter and an equilateral triangle, it's essential to start by identifying the given elements. The discussion highlights that if two arcs are congruent, the angles subtending those arcs must also be equal. Additionally, if all three arcs are of equal length, it indicates that the triangle formed is equilateral. The presence of a bisector is suggested as a key component in establishing congruence. Understanding these relationships is crucial for completing the proof.
srk
Messages
1
Reaction score
0
View attachment 5015

Not sure how to solve considering nothing is given as perpendicular or bisected.
Is anyone aware on how to solve this problem?

~S.R.K.
 

Attachments

  • 11.jpg
    11.jpg
    61.5 KB · Views: 111
Mathematics news on Phys.org
Well, to start with list what is given, then look at similar components
 
I think you will see that KH is a bisector and that will all angles equal and the sides equal
 
Last edited:
If two arcs are congruent, what must be true about the angles that subtend the arcs?
 
srk said:
Not sure how to solve considering nothing is given as perpendicular or bisected.
Is anyone aware on how to solve this problem?

If all three arcs have the same length, then the triangle is equilateral.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...

Similar threads

Back
Top