Solve Quadratic Function with Factor Theorem

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The discussion revolves around solving a quadratic function f(x) with specific properties, including f(3/2)=0, (x-2) as a factor, and f(4)=50. The solution provided is f(x)=5(2x-3)(x-2), where the factor of "5" is crucial to satisfy the condition f(4)=50. Participants clarify that substituting x=4 into the function reveals the need for the constant A, which equals 5. This indicates that the function cannot simply be (2x-3)(x-2) without the multiplier. The final understanding emphasizes the importance of the constant in meeting all given criteria.
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This is the problem:

A quadratic function f(x) with integral coefficients has the following properties: f(3/2)=0, (x-2) is a factor of f(x), and f(4) = 50. Determine f(x).

The answer in the back of the book is f(x)=5(2x-3)(x-2)

I can easily understand the (2x-3) and (x-2), but I don't understand the "5", and "f(4) = 50".
 
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f(4) = 50 means that the quadratic function evaluated at x = 4 has a value of 50. Your final solution must satisfy this condition as well as the others.

Hint, the "5" probably has something to do with that last criterion.
 
Hmm, when you sub f(4) = 50 in f(x)=(2x-3)(x-2)

You end up with 50=10


Am I on the right track towards implementing that "5" into my final equation?
 
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Which tells you that f(x) is NOT (2x-3)(x-2)!

But you also know that 2x-3 and x- 2 are the only factors involving x.
What happens if you substitute x= 4 into f(x)= A(2x-3)(x-2) where A is a constant?
 
One word to describe HallsofIvy.. Brilliant!

You end up with A=5, thanks I understand it now :D
 
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