Solve Redox Titration Problem w/ NaNO2 & KMnO4 - Help Needed!

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The discussion revolves around solving a redox titration problem involving potassium permanganate (KMnO4) and sodium nitrite (NaNO2). The balanced chemical equation is essential for determining the stoichiometric relationships between the reactants. To find the molar concentration of sodium nitrate, the number of moles of KMnO4 used must be calculated first, followed by the stoichiometric amount of NaNO2. The final concentration is obtained by dividing the moles of NaNO2 by its volume in liters (0.02 L). Understanding stoichiometric calculations is crucial for successfully completing this chemistry problem.
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I have many problesm with this question. Can somone help me please?

In a titration of patasium permanganate soloution with acidified sodium nitrate solution

MnO4- + BO2- H+ -----> Mn+2 + NO3- +H2O

45 ml of 0.05M of KMnO4 reacts complitely with 20.0 mL of NaNO2 solution.

Calculate the molat concentration of sodium nitrate.

Please give me a hand with this. I relly need help to pass my chimetry curse.
 
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You must start with balanced equation. Once it is balanced calculate number of moles permanganate used and stoichiometric amount of sodium nitrate. Latter divided by 0.02L will give you concentration.
 
Sorry but I kinda dontt understand how to get the stoichiometric amount of sodium nitrate. And what do I have to divide by 0.02L. Sorry it's just I kinda not that good at chemestry.
 
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