Solve Simple Limit Problem: (1/x)-(1/2)÷(x-2)

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lim x=>2

(1/x) - (1/2)
------------
x-2I was looking through my notes and found this problem. It shows the answer to be -.25, but I don't see how they got that. I know I want to cancel out the (x-2) on both sides of the division bar, but I'm not sure how to do this. Can anyone help me out? Thanks!
 
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arildno said:
Have you learned about L'hopital's rule yet?
If you haven't, let your first step be to write your numerator as a single fraction.

No, never heard of him, sorry.

HallsofIvy said:
L'Hopital's rule is "overkill" here!

Arildno's second suggestion, writing
[tex]\frac{1}{x}- \frac{1}{2}[/tex]
as a single fraction is best. What is the common denominator?

I only see a common numerator of 1 not denominator.

Can I do this:

[tex]\frac{-1}{x-2}[/tex] ?
 
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swears said:
No, never heard of him, sorry.



I only see a common numerator of 1 not denominator.

Can I do this:

[tex]\frac{-1}{x-2}[/tex] ?
HORROR OF HORRORS!

NEVER EVER MISTREAT FRACTIONS IN THAT MANNER! :mad: :mad: :mad: :mad:
 
umm, OK.

Can someone else help me out?
 
yes, x is a variable. 1/2 is a fraction.
 
Riight. Well, are you going to correct me, or just keep criticizing?
 
I've been looking at this problem for an hour, I obviously don't know how to do it.
 
arildno said:
Look at [itex]\frac{1}{x}-\frac{1}{2}[/itex]
How many fractions do you have in this expression?

2 fractions
 
-"this message is too short"- 1?
 
i'll give you a hint or two
[tex]\frac{\frac{1}{x} - \frac{1}{2}}{x-2}[/tex]
[tex]=\frac{\frac{2}{2x} - \frac{x}{2x}}{x-2}[/tex]
[tex]=\frac{\frac{2-x}{2x}}{x-2}[/tex]
[tex]=\frac{\frac{-(x-2)}{2x}}{x-2}[/tex]
[tex]=-\frac{1}{2x}[/tex]
then substitue x=2 in there to get your answer of -.25
where i have used the following
[tex]\frac{\frac{a}{b}}{c}=\frac{a}{bc}[/tex]
[tex]2-x=-(x-2)[/tex]
[tex]\frac{a}{b}-\frac{c}{d}=\frac{ad-bc}{bd}[/tex]
[tex]\frac{a}{c} - \frac{b}{c} = \frac{a-b}{c}[/tex]
 
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Thanks for your help. I'm going to try and soak this in and figure out how u did that.
 
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yeah you can do that because for example
[tex]\frac{1\times 2}{2\times 2} = \frac{2}{4}=\frac{1}{2}[/tex]
 
Cool, Thanks so much. I totally forgot about that Lowest Common Denominator thing.