Solve Simple Trigo Probs: Minimum Value & Proving Sin Product

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Homework Help Overview

The discussion revolves around two trigonometric problems: finding the minimum value of the expression 9tan²θ + 4cot²θ and proving the identity sin20°sin40°sin60°sin80° = 3/16.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the expression for the minimum value, with one suggesting a transformation to a squared form. Another participant elaborates on the reasoning behind using squares to find minimum values.

Discussion Status

There is an ongoing exploration of the first problem, with some participants providing insights into the reasoning behind their approaches. The second problem has not yet been addressed in detail, and no consensus has been reached on either problem.

Contextual Notes

Participants are encouraged to show their work before receiving guidance, adhering to the forum's policy on homework help.

ron_jay
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Help needed to solve these:

1)what is the minimum value of the expression 9tan^2 [tex]\theta[/tex] + 4cot^2 [tex]\theta[/tex] ?

2)Prove that sin20.sin40.sin60.sin80 =3/16
 
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Please show us how you would approach each of these problems. We must see your work first, in order for us to provide tutorial help. We do not furnish answers to homework and coursework questions here on the PF.
 
1. [tex]9 \tan^{2} \theta + 4 \cot^{2} \theta =(3 \tan \theta - 2 \cot \theta)^{2}+12 \geq 12[/tex] with equality holding when [tex]|\tan \theta|=\sqrt{\frac{2}{3}}[/tex] sorry i didn't see berkeman's post
 
To add a little understanding to pardesi's post, he wrote the expression in the form [tex](3 \tan \theta - 2\cot \theta)^2 + 12[/tex] because even though cot and tan don't have minimum values, squares do (in the real numbers, but that's a different matter). 12 is a constant we can't change that. We know squares are more or equal to 0. So the smallest value would be if the square was 0.

So you set 3 tan x = 2 cot x. If you can find a solution, which pardesi did, then there is a value for which it is 0. Done :)
 

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