# Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum

• MHB
• Wilmer
In summary, the first shooter's name is "Don", the RSB shooter is younger than Bob, the distance in inches from Bob's SB to the RSB is 72, and from Daly's SB to the BSB is 97.
Wilmer
Art, Bob, Cal and Don (ages and last names not necessarily in order:
31 32 33 34, Baum Baxter Daly Neary) each decide to shoot a sticky
spitball at the wall across the beverage room.

To permit this (else this puzzle could not be devised and you'd all
be disappointed) 4 spitballs magically appear on their table:
a Blue SpitBall (BSB), a green one (GSB), a red one (RSB) and
a white one (WSB).

OK: the shooting's done; believe it or not, here's how the SB's stuck:
-Don's SB directly right of the RSB and directly below Baum's SB
-Neary's directly below RSB, Don's 72 inches from Baxter's
-Art's 97 inches from Neary's and 35 inches from GSB

It is entirely possible that you'll need these clues:
-Bob is younger than the RSB shooter, Daly younger than WSB shooter
-Cal is older than BSB shooter, Art older than Baxter

What is the first name of the oldest shooter,
the distance in inches from Bob's SB to the RSB,
and from Daly's SB to the BSB?

In case I forget it!
Interpreting the clues properly will force Art as the oldest,
and place the spitballs a bit like this:
Code:
                                             sb1
sb2                      sb3                    sb4
...which gives you two 90 degree triangles:
(sb1 to sb3) = 35, base = 72, (sb1 to sb4) = 97.
Solve to get (sb2 to sb4) = 30, (sb3 to sb4) = 78.
sb1: Art Baum, white
sb2: Cal Baxter, red
sb3: Don Daly, green
sb4: Bob Neary, blue

Wilmer said:
Art, Bob, Cal and Don (ages and last names not necessarily in order:
31 32 33 34, Baum Baxter Daly Neary) each decide to shoot a sticky
spitball at the wall across the beverage room.

To permit this (else this puzzle could not be devised and you'd all
be disappointed) 4 spitballs magically appear on their table:
a Blue SpitBall (BSB), a green one (GSB), a red one (RSB) and
a white one (WSB).

OK: the shooting's done; believe it or not, here's how the SB's stuck:
-Don's SB directly right of the RSB and directly below Baum's SB
-Neary's directly below RSB, Don's 72 inches from Baxter's
-Art's 97 inches from Neary's and 35 inches from GSB

It is entirely possible that you'll need these clues:
-Bob is younger than the RSB shooter, Daly younger than WSB shooter
-Cal is older than BSB shooter, Art older than Baxter

What is the first name of the oldest shooter,
the distance in inches from Bob's SB to the RSB,
and from Daly's SB to the BSB?

From the clues, the configuration of the SBs on the wall would appear to be the following:
$$\begin{array}{llll} {} & {} & {} & \bullet\ \text{Baum} \\ {} & {} & {} & {} \\ \bullet\ \text{RSB} & {} & {} & \bullet\ \text{Don} \\ {} & {} & {} & {} \\ \bullet\ \text{Neary} & {} & {} & {} \end{array}$$
So Don is not Baum or Neary; he’s not Baxter either, whose SB is 72 inches away. Therefore Don is Daly, and Baxter’s is the RSB.

Art is not Neary (whose SB is 97 inches away) so he’s either the RSB shooter or Baum. But he can’t be the former since we now know that the RSB shooter is Baxter and Art is older than Baxter. Therefore Art is Baum.

This leaves Bob and Cal as Baxter and Neary. Bob is not the RSB shooter, who is older than Bob and who we know is Baxter; therefore Bob is Neary, leaving Cal as Baxter.

The oldest shooter can’t be Bob Neary or Don Daly, each of whom is younger than somebody else; nor is it Cal Baxter, than whom Art Baum is older. Therefore $\fbox{Art is the oldest}$.

Now, some geometry. Art Baum’s SB is 97 inches from Bob Neary’s, and 35 inches from the GSB; looking at the diagram, the GSB has got to be Don Daly’s. Let the distance between Neary’s SB and the RSB be $x$ inches; then Pythagoras’s theorem gives
$$(35+x)^2+72^2\ =\ 97^2$$
$\implies\ x\ =\ 30$.

So Bob’s SB is $\fbox{30 inches}$ from the RSB.

Finally, we work out who shot the BSB. He is younger than Cal Baxter and so can’t be Cal Baxter – or Art Baum, who we now know is the oldest. We also now know that Don Daly shot the GSB. Therefore it was Bob Neary. By Pythagoras again, his SB is $\sqrt{30^2+72^2}\ =\ \fbox{78 inches}$ from Daly’s SB.

YES! Your solution is kinda same as mine;
BUT "looks" much better!

## 1. What is "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum"?

"Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum" is a puzzle game that involves solving a sticky spitball puzzle featuring four characters named Bob, Cal, Don, and Baum. The goal of the game is to arrange the spitballs in a specific order to reveal a hidden image.

## 2. How do you play "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum"?

To play "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum", you must first arrange the spitballs in the correct order to reveal the hidden image. To do this, you can click and drag the spitballs to move them around. Once you have the correct arrangement, the hidden image will be revealed.

## 3. Is "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum" suitable for all ages?

Yes, "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum" is suitable for all ages. It is a fun and challenging puzzle game that can be enjoyed by both children and adults.

## 4. Are there any tips for solving "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum"?

One tip for solving "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum" is to start by focusing on one character at a time. This will help you to visualize the correct arrangement of the spitballs for each character. You can also use the hint button for assistance if you get stuck.

## 5. Can "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum" be played on mobile devices?

Yes, "Solve Sticky Spitballs Art Puzzle: Bob, Cal, Don & Baum" can be played on mobile devices. The game is compatible with both iOS and Android devices, making it easy to play on the go.