Solve the given problem involving conditional probability

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SUMMARY

The discussion centers on solving a problem involving conditional probability with two boxes, X and Y, containing white and black balls. The probabilities derived include \( P_r(w) = \frac{n-3}{n} \) for box X and \( P_r(w) = \frac{4}{n+1} \) for box Y, leading to the combined probability \( P_r(w) = \frac{4(n-3)}{n(n+1)} \). Participants emphasize the importance of considering both conditions where the ball taken from box X is either black or white, ultimately leading to the final probability expression \( P_{Required} = \frac{4n-3}{n(n+1)} \) for various values of n.

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  • #31
Ehm, not so cheerful here, check your post #18 again, P(W) is the addition of those two.
 
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  • #32
Delta2 said:
Ehm, not so cheerful here, check your post #18 again, P(W) is the addition of those two.
Yes, i am aware that ##P(W)= \dfrac{4n-3}{n(n+1)}## is the addition given by

##P(X=B,Y=W) = \dfrac{3}{n} × \dfrac{3}{n+1}= \dfrac{9}{n(n+1)}##

and##P(X=W,Y=W) = \dfrac{n-3}{n} × \dfrac{4}{n+1}= \dfrac{4(n-3)}{n(n+1)}##

My post ##30## is correct.
 
  • #33
yes ok right, it is ##4n-3## there i thought you had ##4(n-3)##.
 
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