Solve the trig equations 2sin^2(x) + sin(x) - 1 =0

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Homework Help Overview

The problem involves solving the trigonometric equation 2sin²(x) + sin(x) - 1 = 0 within the interval 0 ≤ x ≤ 2π. The subject area is trigonometry, specifically focusing on equations involving sine functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the nature of the equation as quadratic in terms of sin(x) and consider the application of the quadratic formula. There is mention of using trigonometric identities to find solutions.

Discussion Status

Some participants have expressed understanding of the problem and indicated they believe they have found the correct answers. There is a suggestion to verify solutions by substituting back into the original equation, but no explicit consensus on the solutions has been reached.

Contextual Notes

The original poster mentions a lack of familiarity with solving trigonometric equations that involve more than one sine function, which may influence their approach to the problem.

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Homework Statement



Find all values of x in the interval 0<=x<=2pi for which 2sin^2(x)+sin(x)-1=0.

Homework Equations





The Attempt at a Solution



I have no idea.

I spent awhile trying to figure it out on my graphics calculator but couldn't figure it out.

I have only been told how to solve trig equations where there is 1 trig function, lol.

any help would be great thanks.
 
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This equation is quadratic, the variable is sin(x). Can you solve now?
 
ax^2+bx+c=0

quadratic formula ...

for trig

x=trig identity
 
o rite i see.

I think I have the right answers lol

cheeers
 
Trail_Builder said:
o rite i see.

I think I have the right answers lol

cheeers
You can always check it by plugging it back into your original equation.
 

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