Solve Tricky Integration: Compute Value of 1∫g(ln(t))/t dt

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SUMMARY

The integral 1∫g(ln(t))/t dt can be computed using the technique of u-substitution, where u = ln(t) and du = 1/t dt. Given that the integral of g(t) from 0 to 1 equals 5, the bounds of integration must be adjusted accordingly. When t = 1, u becomes 0, and when t approaches 0, u approaches negative infinity. This transformation allows for the evaluation of the integral using the known value of g(t).

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Homework Statement



Suppose that the 0[tex]\int[/tex]1 g(t)dt=5.
Compute the value of 1[tex]\int[/tex]e g(ln(t))/t dt

Homework Equations


The Attempt at a Solution


I think that u substitution is the best way to solve.
If you set u=ln(t), then du=1/t dt which is in your integration. I do not know how to incorporate the given value of the integral of g(t) into the second integration, especially because the bounds of integration are different.

Thank you for any help!
 
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When you u-substitute, substitute your boundaries as well. For example, when t = 1, what is ln(t)? Repeat with e.
 

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