Solve v/(v-1)^2 Integral: Tips & Tricks

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Homework Help Overview

The discussion revolves around the integral of the function v/(v-1)^2, exploring various methods of integration and the challenges faced in solving it.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of partial fractions as a method for integration, with one suggesting a different approach by substituting t = v - 1. There are inquiries about the original poster's attempts and reasoning behind their struggles with the integral.

Discussion Status

The discussion includes multiple approaches being explored, with some participants offering alternative methods without reaching a consensus. There is an acknowledgment of the original poster's difficulties and suggestions for clarification on their previous attempts.

Contextual Notes

Participants are working within the constraints of homework rules, and there is an emphasis on understanding the integral rather than providing a direct solution.

mundo44
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Cannot figure out the integral of : v/(v-1)^2


I tried partial fractions then integrating but didn't get me anywhere! HELP!
 
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Partial fractions should work...why not post what you've got?
 
Try to solve for A and B: v/(v-1)^2 = A/(v-1) + B/(v-1)^2
 
simplest solution:

let t=v-1
dt =dv
function now becomes Integrate[(t+1)^2/t dt]

no partial fractions needed
 
elduderino said:
simplest solution:

let t=v-1
dt =dv
function now becomes Integrate[(t+1)^2/t dt]

no partial fractions needed

If the original integral is:


[tex]\int{\frac{v}{(v-1)^2}}[/tex]

[tex]t=v-1 ; v=t+1[/tex]

[tex]dv=dt[/tex]

[tex]\int{\frac{t+1}{t^2}[/tex]

Now separate on two fractions and solve two integrals.
 
yeah.. sorry for tht mistake :P
 

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