Solve v/(v-1)^2 Integral: Tips & Tricks

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mundo44
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Cannot figure out the integral of : v/(v-1)^2


I tried partial fractions then integrating but didn't get me anywhere! HELP!
 
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Try to solve for A and B: v/(v-1)^2 = A/(v-1) + B/(v-1)^2
 
simplest solution:

let t=v-1
dt =dv
function now becomes Integrate[(t+1)^2/t dt]

no partial fractions needed
 
elduderino said:
simplest solution:

let t=v-1
dt =dv
function now becomes Integrate[(t+1)^2/t dt]

no partial fractions needed

If the original integral is:


[tex]\int{\frac{v}{(v-1)^2}}[/tex]

[tex]t=v-1 ; v=t+1[/tex]

[tex]dv=dt[/tex]

[tex]\int{\frac{t+1}{t^2}[/tex]

Now separate on two fractions and solve two integrals.
 
yeah.. sorry for tht mistake :P