Solve Velocity Problems: Homework Statement & Equations

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SUMMARY

The discussion focuses on solving velocity problems involving distance and average velocity calculations for both an automobile and a train. The key equations used are based on the formula d=vt, where 'd' represents distance, 'v' is velocity, and 't' is time. The total distance covered by the automobile is 540 km, with an average velocity of 10.7 m/s North. For the train, the displacement after the first three hours is 360 km North, with various average velocities calculated for different segments of the trip.

PREREQUISITES
  • Understanding of the formula d=vt for distance, velocity, and time calculations
  • Basic knowledge of unit conversions between kilometers per hour and meters per second
  • Familiarity with vector directions (North, South, etc.) in motion problems
  • Ability to perform arithmetic operations with time and distance
NEXT STEPS
  • Learn how to convert kilometers per hour to meters per second for velocity calculations
  • Study vector addition and subtraction in physics for displacement problems
  • Explore more complex motion problems involving acceleration and deceleration
  • Practice solving real-world problems using the d=vt equation in various contexts
USEFUL FOR

Students studying physics, particularly those focusing on kinematics and motion problems, as well as educators seeking to clarify concepts related to distance and velocity calculations.

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Homework Statement


An auto travels at the rate of 25 km/hr North for 4 hours, then at 50 km/hr North for 8 hours, and finally 20 km/hr North for 2 hours. Find (a) the total distance covered in km and (b) the average velocity for the complete trip in m/s.


Homework Equations


d=vt


The Attempt at a Solution


>
v1= 25 km/hr N
t = 4 hrs
>
d=vt
d1=(25km/hrN)(...)
If someone can just work through this and tell me what things mean and why that would be great.


4. Answer from Teacher
540 km; 107(or 10.7) m/s N


Homework Statement


A train travels at an average velocity of 120 km/h for 3 hours, then at 80 km/h for 210 km. The train stop for 1 hour. Finally, the train covers 300 km in 2.9 hours. All motion is to the NORTH. (a) What is the train's displacement at the end of the first 3 hours? (b) How much time was spent going 80 km/h in the second leg of the trip? (c) What was the average velocity for the final 3.9 hours of the trip? (d) Calculate the average velocity for the whole trip. (e) Calculate the average velocity if the second part of the trip (80 km/h for 210 km) were to the SOUTH.


Homework Equations


d=vt


The Attempt at a Solution


Honestly, with this question I have no clue what to do. Same as above, if someone can help me go through this that would be great.


4. Answer from Teacher
360 km N; 2.6 hr; 103.4 km/hr N; 91.6 km/hr W; 47.4 km/hr N
 
Last edited:
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Jath said:

Homework Statement


An auto travels at the rate of 25 km/hr North for 4 hours, then at 50 km/hr North for 8 hours, and finally 20 km/hr North for 2 hours. Find (a) the total distance covered in km and (b) the average velocity for the complete trip in m/s.

Homework Equations


d=vt

The Attempt at a Solution


>
v1= 25 km/hr N
t = 4 hrs
>
d=vt
d1=(25km/hrN)(...)
If someone can just work through this and tell me what things mean and why that would be great.4. Answer from Teacher
540 km; 107(or 10.7) m/s N

For part A:

Break it down,

25 km/hr North for 4 hours = 100km for 4 hours
50 km/hr North for 8 hours = 400km for 8 hours
20 km/hr North for 2 hours = 40km for 2 hours

Total km = 540km

Do you understand what I did there?
 
I do but my teacher wants me to do it in equations, like how I wrote in the attempt at solution, v1 = ... , t = ... and etc. When I do this I get confused of what to multiply by and etc. Also with directions, like E, N and etc, do these change the problems drastically or very little? How too.
 

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