- #1
Rusk1
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[SOLVED] Friction problem
Car is moving down a 10degree slope and applies the breaks. The net force acting on the car as it stops is -2.0 x 10^4 N. coefficient of kinetic friction is .797. What is the mass? what is the magnitude of the normal force?
Fnet=M*Anet=Fapplied - Fk
Fk= muk*m*a = muk*Fn
M= (Fapplied/Anet + mukG)
i think that would be it
i tried doing this many ways but always seem to get it wrong. I quess I don't understand what the net force actually is. It is not equal to Fk. This is probably a lot simpler and I'm putting too much thought into it.
Homework Statement
Car is moving down a 10degree slope and applies the breaks. The net force acting on the car as it stops is -2.0 x 10^4 N. coefficient of kinetic friction is .797. What is the mass? what is the magnitude of the normal force?
Homework Equations
Fnet=M*Anet=Fapplied - Fk
Fk= muk*m*a = muk*Fn
M= (Fapplied/Anet + mukG)
i think that would be it
The Attempt at a Solution
i tried doing this many ways but always seem to get it wrong. I quess I don't understand what the net force actually is. It is not equal to Fk. This is probably a lot simpler and I'm putting too much thought into it.