Solved: Probability of Achieving 6 in 24 Throws of 2 Dice

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SUMMARY

The discussion centers on calculating the probability of achieving at least one pair of sixes when rolling two dice 24 times. The correct approach involves recognizing that the probability of rolling a pair of sixes in a single throw is 1/36. The user initially attempted to use a formula involving the binomial distribution but realized that the problem specifically asks for the probability of achieving at least one pair of sixes, necessitating a different calculation method. The final understanding emphasizes the need to calculate the complement probability of not rolling a pair of sixes across all throws.

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sacuan
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Homework Statement



probability to achieve a couple of 6 launching a couple of dies for 24 times

Homework Equations



why i cannot calculate this as:
1/36 * (35/36)EXP23 * (24!/23!)


The Attempt at a Solution



it should be correct:
a="to achive a couple of 6 in 1 throw"
e="never achive a coule of 6 in 24 throws"
i can calculare p(a)=1/36
i can calculate p(e)=[1-p(a)]EXP24
so 1-p(e) should be my correct result
 
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Unless I'm missing something, it seems you can treat this like a Bernoulli scheme with the probability p = 1/36.
 
i understand by myself

the exact text is of the problem is:

probability to achieve AT LEAST a couple of 6 launching a couple of dies for 24 times

so now i understand why i cannot use it

thank you
 

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