Solving 4x3 + 4y =0 and 4y3 + 4x =0: Explained!

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Homework Help Overview

The problem involves solving a system of equations: 4x³ + 4y = 0 and 4y³ + 4x = 0. The original poster expresses confusion regarding how the solutions x = 0, 1, -1 and y = 0, -1, 1 were derived.

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss methods for isolating variables and substituting them into the equations. There are attempts to simplify the equations and factor polynomials, with some questioning algebraic steps and seeking clarification on how to proceed after certain transformations.

Discussion Status

The discussion is active, with participants providing guidance on algebraic manipulation and factoring. There is a focus on correcting mistakes and exploring different approaches to solving the equations, though no consensus has been reached on a complete method.

Contextual Notes

Some participants note algebraic errors and the need for simplification, while others express uncertainty about the next steps in the problem-solving process. The original poster and others are seeking further clarification and assistance.

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Homework Statement



how to solve this:

4x3 + 4y =0
4y3 + 4x =0


the solution is x = 0,1,-1
y = 0,-1,1

how did they bring such result :bugeye:
 
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rabihtawil said:

Homework Statement



how to solve this:

4x3 + 4y =0
4y3 + 4x =0


the solution is x = 0,1,-1
y = 0,-1,1

how did they bring such result :bugeye:

Find y from the first equation and then plug it into the second one so you're done!

AB
 
Altabeh said:
Find y from the first equation and then plug it into the second one so you're done!

AB

4x3 + 4y =0
x3 + y=0
y=x3

NOW... plugging in

4y3 + 4x =0
y3 + x=0
(x3)3 + x = 0

now what?? how do i continue from here :S
 
First, fix your algebra mistake. You dropped a sign. Once you fix that, you'll find you can factor the polynomial and solve for its roots.
 
vela said:
First, fix your algebra mistake. You dropped a sign.

4x3 + 4y =0
x3 + y=0
y=-x3

NOW... plugging in

4y3 + 4x =0
y3 + x=0
(-x3)3 + x = 0

vela said:
Once you fix that, you'll find you can factor the polynomial and solve for its roots.

Please i am stuck show me how, i know it should be factored by x but how?
 
Last edited:
First, simplify (-x3)3. What do you get?
 
vela said:
First, simplify (-x3)3. What do you get?

-x9 + x = 0

now what?
 
rabihtawil said:
-x9 + x = 0

now what?

-x9 + x = 0
x(-x8 + 1) = 0

x = 0 or x= 1 right?
 
You can flip the sign of the whole equation to make it a little simpler to work with:

x9-x=0

Now you have a common factor of x in both terms, so factor it out.

OK, you posted while I was writing. :) So you have

x(x8-1) = 0

So this means x=0 or x8-1=0, right? So you have one of the roots so far.

Note that x8-1=(x4)2-12 is a difference of squares, so what does it factor into?
 
  • #10
Thank you so much, very appreciated!
 

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