- #1

raptik

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## Homework Statement

Two masses M

_{1}= .600kg and M

_{2}= 2.2kg connected by a cord of negligible mass and passes over a frictionless pulley of negligible mass. Assuming that y-axis has a positive upward direction, what is the tension in the cord?

## Homework Equations

F = ma

W = mg

## The Attempt at a Solution

I first tried to add up the F

_{g}for both masses under the assumption that the opposing force would be the tension.

I then subtracted the larger F

_{g}from the smaller F

_{g}which was also wrong.

I then came upon https://www.physicsforums.com/showthread.php?t=201258" and tried to follow the process discussed there. I tried to solve for a based on the posts discussed in the other thread but was lost on posts 9 and 10 (NEwayz, back to what I did).

I found the equations of the two blocks to be T - m

_{1}g = m

_{1}a and m

_{2}g - T = m

_{2}a.

this makes T = m

_{1}a + m

_{1}g = m

_{2}g - m

_{2}a.

Plugging in the numbers gives 5.88N + .6a = 21.56N - 2.2a

solving for a gives a = 5.6ms

^{-2}

Plugging this back into the T equation gives a T of 9.24N

I then double the T because there is T working on both ends of the rope and get 18.48N.

I turns out that this is an incorrect answer and I am now out of ideas. Please help.

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