Solving a complex numbered cubic equation

  • Thread starter Thread starter PcumP_Ravenclaw
  • Start date Start date
  • Tags Tags
    Complex Cubic
Click For Summary
The discussion focuses on solving the cubic equation z^3 − z^2 + z − 1 = 0, first by inspection and then through algebraic methods. The solution by inspection suggests that z = 1 is a valid root, which can be verified by substituting it back into the equation. There is confusion regarding the number of solutions, as the equation has six solutions for the variable ζ, not z, due to the nature of cubic equations and their roots in the complex plane. The mention of cube roots indicates that while each cubic equation has three roots, the context here refers to the complex solutions that arise from the polynomial's structure. Overall, the discussion clarifies the distinction between the roots of the cubic equation and the solutions derived from its transformations.
PcumP_Ravenclaw
Messages
105
Reaction score
4

Homework Statement


Solve the equation ## z^3 − z^2 + z − 1 = 0 ## first by inspection, and then by the
method described above. where Z is a complex number. (Alan F. Beardon, Algebra and Geometry)

The method described above is shown in the attachment.

Homework Equations


The method is shown in the attachment.

The Attempt at a Solution



Solve by inspection means to draw the graph of this equation and check where it intersects the x axis??
Shown in the attachment. the solution is 1 if i am not wrong

My algebraic solution is different. why? My attempt is also in the attachement.

Can you please also explain why there are six solutions for ## z ## when #z^3# has two solutions because of quadratic equation. cube root of any number has only one solutions which is the number itself. e.g. ## \sqrt[3]{-1} = -1*-1*-1 or \sqrt[3]{1} = 1*1*1## so cube root only gives one solution then what do they mean by six solutions??


danke...
 

Attachments

  • cubic.jpg
    cubic.jpg
    60.1 KB · Views: 580
  • graph3.jpg
    graph3.jpg
    33.9 KB · Views: 555
  • cubicsolutions.jpg
    cubicsolutions.jpg
    24.7 KB · Views: 534
Physics news on Phys.org
By inspection means just that: look at the terms of the equation and substitute some guesses which can be evaluated using mental arithmetic.

For the equation in the OP, looking at how the signs of the terms alternate, guessing that z = 1 is a solution is a solid hunch, since the magnitudes of z, z2, and z3 are all 1.
 
  • Like
Likes ComplexVar89
"By inspection" often means just trying simple numbers. What do you get if you put z= 1 into the equation?
 
Or you could look at the fist two terms, then look at the second two terms and notice these paddies have, er, a something in common. ;)
 
Last edited:
PcumP_Ravenclaw said:
Can you please also explain why there are six solutions for ## z ##
It does not say there are six solutions for z. It says there are six solutions for ##\zeta##, but pairs of these produce the same value for z.
 

Similar threads

  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 20 ·
Replies
20
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K